题解 | #单链表的排序#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 the head node
# @return ListNode类
#

class Solution:
    def sortInList(self , head: ListNode) -> ListNode:
        # write code here
        sortthis = head
        sortlist = []
        while sortthis:
            sortlist.append(sortthis.val)
            sortthis = sortthis.next
        sortlist.sort()
        newhead = ListNode(sortlist[0])
        this = newhead
        for i in range(1,len(sortlist)):
            this.next = ListNode(sortlist[i])
            this = this.next
        return newhead