题解 | #Redraiment的走法#
Redraiment的走法
https://www.nowcoder.com/practice/24e6243b9f0446b081b1d6d32f2aa3aa
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int[] a = new int[n]; for (int i = 0; i < n; i++) { a[i] = sc.nextInt(); } //dp[j]表示以下标j为起点,最多走的步数 int[] dp = new int[n]; int max = 0; for (int j = n - 1; j >= 0; j--) { dp[j] = 1; for (int k = n - 1; k > j; k--) { if (a[j] < a[k]) { dp[j] = Math.max(dp[j], dp[k] + 1); } } max = Math.max(max, dp[j]); } System.out.println(max); } }