题解 | #数值的整数次方#
数值的整数次方
https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param base double浮点型 # @param exponent int整型 # @return double浮点型 # class Solution: def Power(self , base: float, exponent: int) -> float: # write code here if exponent <0: base=1/base exponent=-exponent result =float(1) for i in range(exponent): result*=base return result