题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main() {
int n, i, tmp;
scanf("%d", &n);
for (i=0; i<n; i++){
tmp = 1 << n;
}
printf("%d", tmp);
return 0;
}
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