题解 | #左旋转字符串#
左旋转字符串
https://www.nowcoder.com/practice/12d959b108cb42b1ab72cef4d36af5ec?tpId=13&tqId=23266&ru=/exam/oj/ta&qru=/ta/coding-interviews/question-ranking&sourceUrl=%2Fexam%2Foj%2Fta%3Fpage%3D1%26tpId%3D13%26type%3D13
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param str string字符串
# @param n int整型
# @return string字符串
#
class Solution:
def LeftRotateString(self , str: str, n: int) -> str:
# write code here
if not str:
return ""
#如果移动位数比length大,对length取余数
length=len(str)
if n>length:
n=n%length
Newstr = str[n:]+str[:n]
return Newstr

