题解 | #斐波那契数列#
斐波那契数列
https://www.nowcoder.com/practice/ee5d403c1172487f8c7915b3c3d924c6
# x = int(input())
# def pbnq(x):
# if x == 1 or x ==2:
# return 1
# return pbnq(x-1) + pbnq(x-2)
# print(pbnq(x))
#递归失败，结果运行超时，需要使用数组进行动态规划
k = int(input())
nums = [1,1]
if k <= 2:
print(1)
else:
for x in range(2,k):
nums.append(nums[x-1]+nums[x-2])
print(nums[k-1])
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