题解 | #字符串加密#
字符串加密
https://www.nowcoder.com/practice/e4af1fe682b54459b2a211df91a91cf3
table=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'] s=input() m=input() table2=[] for each in s: if each not in table2: table2.append(each) continue for each in table: if each not in table2: table2.append(each) find={} for i in range(26): key=table[i] value=table2[i] find[key]=value put=[] for each in m: put.append(find[each]) print("".join(put))
建立字典