题解 | #字符串变形#
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param s string字符串 # @param n int整型 # @return string字符串 # class Solution: def trans(self , s: str, n: int) -> str: # write code here def transtr(str): if 97 <= ord(str) <= 122: str = chr(ord(str) - 32) elif 65 <= ord(str) <= 90: str = chr(ord(str) + 32) return str ans = '' flag = None for i in range(1, len(s) + 1): if s[-i]==' ': if i == 1: ans+=' ' flag = -i continue for j in s[-i + 1:flag]: ans += transtr(j) ans += ' ' flag = -i if not s[0]==' ': for j in s[0:flag]: ans += transtr(j) return ans