题解 | #打家劫舍(一)#
打家劫舍(一)
https://www.nowcoder.com/practice/c5fbf7325fbd4c0ea3d0c3ea6bc6cc79?tpId=295&tqId=2285793&ru=/exam/oj&qru=/ta/format-top101/question-ranking&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E7%25AE%2597%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D295
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param nums int整型一维数组 # @return int整型 # class Solution: def rob(self , nums: list[int]) -> int: # write code here length = len(nums) if length==1: return nums[0] dp =[ 0 for i in range(len(nums))] dp[0]=nums[0] dp[1]=max(nums[0],nums[1]) for i in range(2,len(nums)): dp[i] = max(dp[i-2]+nums[i],dp[i-1]) return max(dp)