题解 | #打家劫舍(一)#
打家劫舍(一)
https://www.nowcoder.com/practice/c5fbf7325fbd4c0ea3d0c3ea6bc6cc79?tpId=295&tqId=2285793&ru=/exam/oj&qru=/ta/format-top101/question-ranking&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E7%25AE%2597%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D295
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# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param nums int整型一维数组
# @return int整型
#
class Solution:
def rob(self , nums: list[int]) -> int:
# write code here
length = len(nums)
if length==1:
return nums[0]
dp =[ 0 for i in range(len(nums))]
dp[0]=nums[0]
dp[1]=max(nums[0],nums[1])
for i in range(2,len(nums)):
dp[i] = max(dp[i-2]+nums[i],dp[i-1])
return max(dp)
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