题解 | #24点运算#

s =input().split()
dic=['J','Q','K','A']
value=[11,12,13,1]
inp=[]
if 'joker'in s or 'JOKER' in s:
    print('ERROR')
else:
    for idx,v in enumerate(s):
        if v in dic:
            inp.append(value[dic.index(v)])
        else:
            inp.append(v)
    operate=[]
    def func(sr,idx,res,num,cz):
        if num==3 and res==24:
            global  operate
            operate.append(cz)
            return True
        if idx<3:
            func(sr,idx+1,res+int(sr[idx+1]),num+1,cz+['+'])
        if idx<3:
            func(sr,idx+1,res-int(sr[idx+1]),num+1,cz+['-'])
        if idx<3:
            func(sr,idx+1,res*int(sr[idx+1]),num+1,cz+['*'])
        if idx<3:
            func(sr,idx+1,res//int(sr[idx+1]),num+1,cz+['/'])
    res1=[]
    def qpx(s,l,res):
        if l==0:
            global res1
            res1.append(res)
            return res
        if l>0:
            for i in range(l):
                qpx(s[0:i]+s[i+1:l],l-1,res+[s[i]])
    qpx(inp,4,[])
    p=[]
    for i in res1:
        func(i,0,int(i[0]),0,[])
        if len(operate)>0:
            j = 0
            for sz in i:
                if sz in value:
                    p.append(dic[value.index(sz)])
                else:
                    p.append(sz)
                if j<len(operate[0]):
                    p.append(operate[0][j])
                    j+=1
            break
    if p:
        print(''.join(p))
    else:
        print('NONE')