JZ32 题解 | #从上往下打印二叉树#
从上往下打印二叉树
https://www.nowcoder.com/practice/7fe2212963db4790b57431d9ed259701
/*
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
TreeNode(int x) :
val(x), left(NULL), right(NULL) {
}
};*/
#include <deque>
using namespace std;
class Solution {
public:
vector<int> PrintFromTopToBottom(TreeNode* root) {
vector<int> res;
if (root == nullptr) {
return res;
}
// 二叉树的层序遍历,借助队列保存每一层节点
deque<TreeNode*> myDeque;
myDeque.push_back(root);
while (!myDeque.empty()) {
// 获取队列中的元素长度
int sz = myDeque.size();
// 遍历队列中的每一层节点
for (int i = 0; i < sz; i++) {
TreeNode* front = myDeque.front();
if (front != nullptr) {
res.push_back(front->val);
}
myDeque.pop_front();
if (front->left != nullptr) {
myDeque.push_back(front->left);
}
if (front->right != nullptr) {
myDeque.push_back(front->right);
}
}
}
return res;
}
};

