题解 | #反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
/** * struct ListNode { * int val; * struct ListNode *next; * }; */ /** * * @param pHead ListNode类 * @return ListNode类 */ struct ListNode* ReverseList(struct ListNode* pHead ) { // write code here struct ListNode* Head2, *ptr, *temp, *fptr; if(pHead == NULL) { return NULL; } else if(!pHead->next) { return pHead; } else { fptr = pHead; ptr = pHead->next; pHead->next = NULL; while(ptr->next) { temp = ptr->next; ptr->next = fptr; fptr = ptr; ptr = temp; } ptr->next = fptr; return ptr; } }