题解 | #单链表的排序#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 the head node
# @return ListNode类
#
class Solution:
    def sortInList(self , head: ListNode) -> ListNode:
        # write code here


        if not head:
            return None
        L=[]
        while head:
            L.append(head.val)
            head=head.next
		#利用列表的排序函数排序
        L.sort()
        

#利用列表和构造函数构造链表
        head=ListNode(L[0])
        res =head

        for x in L[1:]:
            node=ListNode(x)
            head.next=node
            head=head.next
        return res