题解 | #删除有序链表中重复的元素-II#

from os import XATTR_REPLACE
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param head ListNode类
# @return ListNode类
#
class Solution:
    def deleteDuplicates(self, head: ListNode) -> ListNode:
        # write code here
        print("******")
        if head == None:
            return None

        L = []
        while head:
            L.append(head.val)
            head = head.next
			
			#在I的基础上将列表中出现次数大于1的元素排除在外，新建一个列表
        L2=[]
        for x in L:
            if L.count(x) >1:
                continue
            else:
                L2.append(x)
        L2.sort()
        print(L)
        if not L2:
            return None
        head = ListNode(L2[0])
        res = head
        for x in L2[1:]:
            node = ListNode(x)
            head.next = node
            head = head.next
        return res