题解 | #删除有序链表中重复的元素-I#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 
# @return ListNode类
#
class Solution:
    def deleteDuplicates(self , head: ListNode) -> ListNode:
        # write code here
        print("******")
        if head==None:
            return None
         
        L=[]
        while head:
            L.append(head.val)
            head =head.next
        L = list(set(L))
        L.sort()
        print(L)

        head=ListNode(L[0])
        res=head
        for x in L[1:]:
            node=ListNode(x)
            head.next=node
            head=head.next
        return res