题解 | #素数判定#
素数判定
https://www.nowcoder.com/practice/5fd9c28b1ce746dd99287a04d8fa9002
#1不是质数
def iszs(n):
for i in range(2, n):
if n % i == 0:
return False
return True
n = int(input())
if iszs(n) and n != 1:
print("yes")
elif n == 1:
print("no")
else:
print("no")
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