题解 | #牛牛学数列2#
牛牛学数列2
https://www.nowcoder.com/practice/fc72951f52984f3abd286d82eeffacba
#include <stdio.h>
int main() {
int n = 0;
double sum = 0;
while (~scanf("%d", &n))
{
for (double i = 1; i <= n; i++)
{
sum += (1 / i);
}
printf("%.6lf", sum);
}
return 0;
}
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