题解 | #牛牛的金币#
牛牛的金币
https://www.nowcoder.com/practice/35d8e3e569dc49f2a1018d1dc9186998
#include <stdio.h> #include <math.h> int main() { int x = 0; int y = 0; int x1 = 0; int y1 = 0; while (4 == scanf("%d %d %d %d", &x, &y, &x1, &y1)) { if (abs(x1 - x) + abs(y1 - y) == 1) { if ((y1 - y) > 0) { printf("u"); } else if ((y1 - y) < 0) { printf("d"); } else if ((x1 - x) > 0) { printf("r"); } else if ((x1 - x) < 0) { printf("l"); } printf("\n"); } } return 0; }