题解 | #记负均正II#
记负均正II
https://www.nowcoder.com/practice/64f6f222499c4c94b338e588592b6a62
#include <stdio.h> int main(){ int n; int count = 0; float nun = 0; int neg = 0; while(scanf("%d", &n) != -1){ if(n < 0){ count++; } else if(n != 0){ neg++; nun += n; } // printf("%.1f\r", nun / neg); } printf("%d\n", count); printf("%.1f\n", nun / neg); return 0; }