题解 | #矩阵乘法#
矩阵乘法
https://www.nowcoder.com/practice/ebe941260f8c4210aa8c17e99cbc663b?tpId=37&tqId=21292&rp=1&ru=/exam/oj/ta&qru=/exam/oj/ta&sourceUrl=%2Fexam%2Foj%2Fta%3Fpage%3D2%26tpId%3D37%26type%3D37&difficulty=undefined&judgeStatus=undefined&tags=&title=
import sys
'''
矩阵A和矩阵B的信息的初始化
'''
Aline = int(input())
Arow = int(input())
Bline = Arow
Brow = int(input())
A = []
B = []
'''
将AB 矩阵的数据添加到列表中
'''
for i in range(Aline):
row = list(map(int,input().split(" ")))
A.append(row)
for i in range(Bline):
row = list(map(int,input().split(" ")))
B.append(row)
def MatrixMultiplication(Aline,Arow,Bline,Brow,A,B):
'''
矩阵的运算结果先遍历A的行,再遍历B的列,再设置一个变量k,K的大小为矩阵A的列数或者B的行数
'''
#初始化一个矩阵C,用来存放运算结果
C=[[0]*Brow for i in range(Aline)]
for i in range(Aline):
for j in range(Brow):
for k in range(Bline):
temp = A[i][k] * B[k][j]
C[i][j] += temp
#print(C)
for i in range(Aline):
for j in range(Brow):
print(C[i][j],end=" ")
#输出完一行以后,打印一个空行,换行输出
print()
MatrixMultiplication(Aline,Arow,Bline,Brow,A,B)

