题解 | #质数因子#

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    long n;
    cin >> n;
    for (int i = 2; i <= sqrt(n); ++i){
        while (n % i == 0){
            cout << i << ' ';
            n /= i;
        }
    }
    if (n > 1){
        cout << n << endl;
    }
    return 0;
}