题解 | #n的阶乘#
n的阶乘
https://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
#include <stdio.h>
/*
获取n的阶乘 注意这个返回值要为long long不然会精度不够
*/
long long factorial(int n){
if(0 == n || 1 == n){
return 1;
}
return n * factorial(n - 1);
}
int main() {
int n;
while (scanf("%d", &n) != EOF) { // 注意 while 处理多个 case
printf("%lld\n", factorial(n));
}
return 0;
}
