题解 | #删除链表的节点#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 
# @param val int整型 
# @return ListNode类
#
class Solution:
    def deleteNode(self , head: ListNode, val: int) -> ListNode:
        # write code here
        pre=head
        cur=head.next

        if head.val ==val:
            return head.next
        else:
            while True:
                if cur.val == val and cur != None :
                    pre.next=cur.next
                    break
                else:
                    pre=cur
                    cur=cur.next
        return head