题解 | #对称平方数1#
对称平方数1
https://www.nowcoder.com/practice/a84d46d5321f4e20931cb725e6c74fad
#include <stdio.h>
int reverse(int k){
int now=k;
int rev=0;
int s=0;
while(now !=0){
s=now %10;
rev=rev*10+s;
now=now/10;
}
return rev;
}
int main(){
int n;
int m;
for (n=0;n<=256;n++){
m=n*n;
if(n*n==reverse(n*n)){
printf("%d\n",n);
}
}
return 0;
}
