题解 | #单链表的排序#

import java.util.*;

/*
 * public class ListNode {
 *   int val;
 *   ListNode next = null;
 * }
 */

public class Solution {
    /**
     * 
     * @param head ListNode类 the head node
     * @return ListNode类
     */
    public ListNode sortInList (ListNode head) {
        // write code here
        List<Integer> list = new ArrayList<>();
        while (head != null) {
            list.add(head.val);
            head = head.next;
        }

        Collections.sort(list);

        ListNode sortHead = new ListNode(0);
        ListNode cur = sortHead;
        for (int i = 0; i < list.size(); ++i) {
            cur.next = new ListNode(list.get(i));
            cur = cur.next;
        }
        return sortHead.next;
    }
}