题解 | #和为S的连续正数序列#

function FindContinuousSequence(sum)
{
    // write code here
    if(sum<=0) return [];

    let seqs=[];
    let n=2;
    while(n**2+n<=2*sum){
        let n0=(2*sum+n-n**2)/(2*n);
        if(Number.isInteger(n0)){
            let seq=[];
            for(let i=0;i<n;i++) seq.push(n0+i);
            seqs.unshift(seq);
        }
        n++;

    }
    return seqs;
}
module.exports = {
    FindContinuousSequence : FindContinuousSequence
};

JavaScript解法