题解 | #浮点数加法#人人都懂的版本
浮点数加法
https://www.nowcoder.com/practice/ddec753f446e4ba4944e35378ba635c8?tpId=61&tqId=29551&tPage=3&ru=/kaoyan/retest/1002&qru=/ta/pku-kaoyan/question-ranking
#include <algorithm>
#include <iostream>
using namespace std;
int cf=0;
string plusf(string x,string y){
int len1=x.size(),len2=y.size();
if(len1<len2){
for(int it=len1;it<len2;it++){
x.insert(x.size(), "0");
}
len1=len2;
}
else if(len2<len1){
for(int it=len2;it<len1;it++){
y.insert(y.size(), "0");
}
len2=len1;
}
//vector<char> resf;resf.clear();
for(int j=len2-1;j>=0;j--){
int m=x[j]-'0',n=y[j]-'0';
int t=(m+n+cf)/10;
x[j]=(m+n+cf)%10+'0';
if(t!=0)
cf=1;
else cf=0;
}
return x;
}
string pluse(string x,string y){
int len1=x.size(),len2=y.size();
if(len1<len2){
for(int it=len1;it<len2;it++){
x.insert(0, "0");
}
len1=len2;
}
else if(len2<len1){
for(int it=len2;it<len1;it++){
y.insert(0, "0");
}
len2=len1;
}
//vector<char> rese;rese.clear();
for(int j=len2-1;j>=0;--j){
int m=x[j]-'0',n=y[j]-'0';
int t=(m+n+cf)/10;
x[j]=(m+n+cf)%10+'0';
if(t!=0)
cf=1;
else cf=0;
}
if(cf==1) x.insert(0,"1");
return x;
}
int main() {
string a,b;
cin>>a>>b;
int d1=a.find('.'),d2=b.find('.');
int l1=a.size(),l2=b.size();
string e1=a.substr(0,d1),f1=a.substr(d1+1,l1-1);
string e2=b.substr(0,d2),f2=b.substr(d2+1,l2-1);
string resf=plusf(f1, f2);
string rese=pluse(e1, e2);
cout<<rese<<"."<<resf<<endl;
return 0;
}
// 64 位输出请用 printf("%lld")
查看25道真题和解析