题解 | #字符串变形#
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param s string字符串 # @param n int整型 # @return string字符串 # class Solution: def trans(self , s: str, n: int) -> str: # write code here s = s.split(" ")[::-1] # print(s) # a = s # for i in s: # print(ord("A"),ord("Z"),ord('a'),ord("z")) # 65 90 97 122 c = [] for i in s: b = "" for j in i: if 65<= ord(j) <= 90: j = j.lower() b += j elif 97 <= ord(j) <= 122: j = j.upper() b += j c.append(b) c = (" ").join(c) a = c return a