题解 | #记负均正#

#include <stdio.h>

int main() {
    int n = 0;
    scanf("%d", &n);    
    int arr[n];
    //输入
    int i = 0;
    for(i=0; i<n; i++)
    {
        scanf("%d", &arr[i]);
    }
    int count1 = 0;//计正数的个数
    int count2 = 0;//计负数的个数
    double sum = 0;//计正整数的和
    //判断
    for(i=0; i<n; i++)
    {
        if(arr[i] > 0)
        {
            sum += arr[i];
            count1++;
        }
        else if(arr[i] < 0)
        {
            count2++;
        }
        else
            ;
    }
    if(sum != 0)
    {
        printf("%d %.1lf", count2,sum/count1);
    }
    else
    {
        printf("%d %.1lf", count2,0.0);
    }

    return 0;
}