题解 | #整数与IP地址间的转换#

整数与IP地址间的转换

https://www.nowcoder.com/practice/66ca0e28f90c42a196afd78cc9c496ea

n1 = input()   # ip地址
n2 = int(input())   # 整数


# 10进制转二级制,仅限8位数,返回字符串
def int_bin_1(n):
    b = ""
    for i in range(7,-1,-1):
        if n >= 2**i:
            n -= 2**i
            b += "1"
        else:
            b += "0"
    return b


# 10进制转二进制,仅限32位数,返回字符串
def int_bin_2(n):
    b = ""
    for i in range(31,-1,-1):
        if n >= 2**i:
            n -= 2**i
            b += "1"
        else:
            b += "0"
    return b

# 二进制转10进制,不限位数
def bin_int(s):
    n = 0
    a = len(s)-1
    for i in s:
        n += int(i) * (2**a)
        a -= 1
    return n



# 1. IP转整数
n1_list = n1.split(".")

b1 = ""
for i in n1_list:
    num = int(i)
    b1 += int_bin_1(num)

print(bin_int(b1))


# 2. 整数转IP
s = int_bin_2(n2)
s1 = bin_int(str(s[0:8]))
s2 = bin_int(str(s[8:16]))
s3 = bin_int(str(s[16:24]))
s4 = bin_int(str(s[24:32]))

print(f"{s1}.{s2}.{s3}.{s4}")

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