题解 | #牛牛的Hermite多项式#
牛牛的Hermite多项式
https://www.nowcoder.com/practice/0c58f8e5673a406cb0e2f5ccf2c671d4
def h(n,x):
if n == 0:
return 1
if n == 1:
return 2
return 2 * x * h(n-1,x) - 2*(n-1) * h(n-2,x)
n,x = map(int,input().split())
print(h(n,x))
