题解 | #牛牛的替换#
牛牛的替换
https://www.nowcoder.com/practice/f2a107dbb99243798d3048a672e8f747
def f(s,a1,a2,a3,a4):
if (a1 not in s) and (a3 not in s):
return s
if a1 in s:
s = s.replace(a1,a2)
if a3 in s:
s = s.replace(a3,a4)
return f(s,a1,a2,a3,a4)
dummy,a1,a2,a3,a4 = input().split()
s = input()
print(f(s,a1,a2,a3,a4))
