题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
import java.util.*;
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param nums int整型一维数组
* @param target int整型
* @return int整型
*/
public int search (int[] nums, int target) {
if(nums.length==0) return -1;
if(nums.length==1 && nums[0]!=target) return -1;
if(nums.length==1 && nums[0]==target) return 0;
if(target == nums[(nums.length+1)/2] ) {
return (nums.length+1)/2;
}
if(target<nums[(nums.length+1)/2] ){
for (int i = 0; i <=(nums.length+1)/2; i++) {
if(target==nums[i]){
return i;
}
}
}
if(target>=nums[(nums.length+1)/2] ){
for (int i = (nums.length+1)/2 ; i < nums.length-1; i++) {
if(target==nums[i]){
return i;
}
}
}
return -1;
}
}

