题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
import java.util.*; public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型一维数组 * @param target int整型 * @return int整型 */ public int search (int[] nums, int target) { if(nums.length==0) return -1; if(nums.length==1 && nums[0]!=target) return -1; if(nums.length==1 && nums[0]==target) return 0; if(target == nums[(nums.length+1)/2] ) { return (nums.length+1)/2; } if(target<nums[(nums.length+1)/2] ){ for (int i = 0; i <=(nums.length+1)/2; i++) { if(target==nums[i]){ return i; } } } if(target>=nums[(nums.length+1)/2] ){ for (int i = (nums.length+1)/2 ; i < nums.length-1; i++) { if(target==nums[i]){ return i; } } } return -1; } }