题解 | #进制转换#
进制转换
https://www.nowcoder.com/practice/8f3df50d2b9043208c5eed283d1d4da6
常规解法1:
hexadecimal = input()
maped = {
"A": 10,
"a": 10,
"B": 11,
"b": 11,
"C": 12,
"c": 12,
"D": 13,
"d": 13,
"E": 14,
"e": 14,
"F": 15,
"f": 15,
}
def cal_hex_to_int(hex_str: str):
handle = hex_str.split("0x")[1]
res = 0
handle_len = len(handle)
for i, v in enumerate(handle):
map_v = maped.get(v, None)
if map_v:
res += map_v * pow(16, handle_len - i - 1)
else:
res += int(v) * pow(16, handle_len - i - 1)
return res
print(cal_hex_to_int(hexadecimal))
解法2: 内置函数int转指定进制
hexadecimal = input() print(int(hexadecimal), 16)
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