题解 | #数字颠倒#

/**********************
*学会利用整形除数和余数的自身特点解题
*********************?
#include <stdio.h>

int main() {
    unsigned int number, t;
    int i = 0, j = 0;
    scanf( "%d", &number );

    if( number == 0 )
    {
        printf("%d",number);
    }
    t = number;
    while( t >= 1 )
    {
        printf( "%d", t % 10 );
        t = t / 10;
    }
    
    return 0;
}