题解 | #人民币转换#

 //这题采用递归的方法，以每四位数为一个阶梯进行递归，直到单位为亿为止
// Write your code here
    while(line =  readline()){
        let obj1={1:'壹',2: '贰',3:'叁',4:'肆',5:'伍',6:'陆',7:'柒',8:'捌',9:'玖'}
        let arr1=['拾', '佰' ,'仟' ,'万' ,'亿']
        let arr2=['元', '角' ,'分' ,'零' ,'整']
        let res=''
        let money =line.split('.')
        if(Number(money[0])==0) {//如果整数部分为零
            if(Number(money[1])>9) res='人民币'+obj1[money[1][0]]+arr2[1]+(Number(money[1][1])>0?obj1[money[1][1]]+arr2[2]:'')
            else res='人民币'+obj1[money[1][0]]+arr2[2]
        }
        else if(Number(money[1])==0) res='人民币'+func(Number(money[0]))+arr2[0]+arr2[4]//整数部分不为0，小数部分为0
        
        else {//均不为0
            if(Number(money[1])>9) res='人民币'+func(Number(money[0]))+arr2[0]+obj1[money[1][0]]+arr2[1]+(Number(money[1][1])>0?obj1[money[1][1]]+arr2[2]:'')
            else res='人民币'+func(Number(money[0]))+arr2[0]+obj1[money[1][1]]+arr2[2]
        }
        console.log(res)
        function func(e){
            if(e<10) return obj1[e]
            else if(e<100) {          
                return (Math.floor(e/10)>1?obj1[Math.floor(e/10)]:'')+arr1[0]+(e%10>0?obj1[e%10]:'')
            }
            else if(e<1000){               
                return obj1[Math.floor(e/100)]+arr1[1]+(e%100>0?e%100>10?func(e%100):(arr2[3]+func(e%100)):'')
            }
            else if(e<10000){               
                return obj1[Math.floor(e/1000)]+arr1[2]+(e%1000>0?e%1000>100?func(e%1000):(arr2[3]+func(e%1000)):'')
            }
            else if(e<1e8){//这是小于一亿的情况，从这里开始采用递归
                return func(Math.floor(e/10000))+arr1[3]+(e%10000>0?e%10000>1000?func(e%10000):(arr2[3]+func(e%10000)):'')
            }
            else if(e>=1e8){//这是大于一亿的情况，这里同样采用递归
                return func(Math.floor(e/1e8))+arr1[4]+(e%1e8>0?func(e%1e8):'')
            }

        }
    }