题解 | #二进制中1的个数#

public class Solution {
    public int NumberOf1(int n) {
        String binNum = Integer.toBinaryString(n);
        int count = 0;
        for(int i=0;i<binNum.length();i++){
            if(binNum.charAt(i)=='1'){
                count++;
            }
        }
        return count;
    }
}