题解 | #扑克牌大小#

while ((line = await readline())) {
    let line1 = line.split("-");
    let a = line1[0].split(" ");
    let b = line1[1].split(" ");
    let arr = [
        "3",
        "4",
        "5",
        "6",
        "7",
        "8",
        "9",
        "10",
        "J",
        "Q",
        "K",
        "A",
        "2",
        "joker",
        "JOKER",
    ];//预定义比较数组
    if (a.length !== b.length) {//这是两手牌数量不相等的情况
        if (
            (a.length == 4 || b.length == 4) &&
            a[0] !== "joker" &&
            b[0] !== "joker"//如果其中一手为炸弹并且不是王炸的时候
        ) {
            a.length == 4
                ? console.log(a.join(" "))
                : console.log(b.join(" "));//炸弹赢
        } else if (a[0] == "joker" || b[0] == "joker") {//如果其中一手为王炸
            a[0] == "joker"
                ? console.log(a.join(" "))
                : console.log(b.join(" "));//王炸赢
        } else console.log("ERROR");//否则无法比较
    } else {//牌的数量相等的情况
        if (a.length == 2) {
            if (a[0] == "joker" || b[0] == "joker")
                a[0] == "joker"//如果牌的数量为2则判断是否为王炸
                    ? console.log(a.join(" "))
                    : console.log(b.join(" "));
            else
                arr.indexOf(a[0]) > arr.indexOf(b[0])//否则按照预定义的数组比较大小
                    ? console.log(a.join(" "))
                    : console.log(b.join(" "));
        } else {若牌的数量不为2则按照预定义的数组比较大小
            arr.indexOf(a[0]) > arr.indexOf(b[0])
                ? console.log(a.join(" "))
                : console.log(b.join(" "));
        }
    }
}