题解 | #自动售货系统#

#究极全面覆盖代码

def f(pq):

    w10,w5,w2,w1 = 0,0,0,0

    while pq>0:

        if pq>=10 and dic_q['10']>=1:

            pq -= 10

            w10 += 1

            dic_q['10'] -= 1

        elif pq>=5 and dic_q['5']>=1:

            pq -= 5

            w5 += 1

            dic_q['5'] -= 1

        elif pq>=2 and dic_q['2']>=1:

            pq -= 2

            w2 += 1

            dic_q['2'] -= 1

        elif pq>=1 and dic_q['1']>=1:

            pq -= 1

            w1 += 1

            dic_q['1'] -= 1

        else:

            pq -= 1

    return pq,w1,w2,w5,w10

s = input().split(';')

dic_m = {'A1':2,'A2':3,'A3':4,'A4':5,'A5':8,'A6':6}

dic_n = {'A1':0,'A2':0,'A3':0,'A4':0,'A5':0,'A6':0}

dic_q = {'1':0,'2':0,'5':0,'10':0}

pq = 0

for i in s[:-1]:

    if i[0] == 'r':

        b = i.split()

        shuliang = b[1].split('-')

        q = b[2].split('-')

        a = 0

        for i in dic_n:

            dic_n[i] = int(shuliang[a])

            a += 1

        c = 0

        for i in dic_q:

            dic_q[i] = int(q[c])

            c += 1

        print('S001:Initialization is successful')

    elif i[0] == 'p':

        pq1 = int(i[2:])

        if pq1 not in[1,2,5,10]:

            print('E002:Denomination error')

        elif dic_q['1']+dic_q['2']*2<pq1 and pq1>2:

            print('E003:Change is not enough, pay fail')

        elif sum(dic_n.values())==0:

            print('E005:All the goods sold out')

        else:

            pq += pq1

            dic_q[str(pq1)] += 1

            print('S002:Pay success,balance=%d'%pq)

    elif i[0]=='b':

        bn = i[2:]

        if bn not in dic_m:

            print('E006:Goods does not exist')

        elif dic_n[bn]==0:

            print('E007:The goods sold out')

        elif dic_m[bn]>pq:

            print('E008:Lack of balance')

        else:

            pq -= dic_m[bn]

            dic_n[bn] -= 1

            print('S003:Buy success,balance=%d'%pq)

    elif i[0]=='c':

        if pq==0:

            print('E009:Work failure')

        else:

            pq,w1,w2,w5,w10 = f(pq)

            print('1 yuan coin number=%d'%w1)

            print('2 yuan coin number='+str(w2))

            print('5 yuan coin number=%d'%w5)

            print('10 yuan coin number=%d'%w10)

    elif i[0] == 'q':

        if ' ' not in i:

            print('E010:Parameter error')

        elif i[2] not in ['0','1']:

            print('E010:Parameter error')

        elif i[2]=='0':

            good = sorted(dic_n,key=lambda x:dic_n[x],reverse=True)

            for i in good:

                print('%s %d %d'%i%dic_m[i]%dic_n[i])

        elif i[2]=='1':

            print('1 yuan coin number=%d'%dic_q['1'])

            print('2 yuan coin number=%d'%dic_q['2'])

            print('5 yuan coin number=%d'%dic_q['5'])

            print('10 yuan coin number=%d'%dic_q['10'])