【C】#KiKi求质数个数#
KiKi求质数个数
https://www.nowcoder.com/practice/d3a404ee0f8d41f98bf4707035d91086
#include <stdio.h>
#include <math.h>
int main() {
int cnt = 0;
for (int i = 101; i <= 999; i += 2) {
int flag = 1;
for (int j = 2; j <= sqrt(i); j++) {
if (i % j == 0) {
flag = 0;
break;
}
}
if (flag == 1)
cnt++;
}
printf("%d", cnt);
return 0;
}
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