题解 | #牛牛的金币#
牛牛的金币
https://www.nowcoder.com/practice/35d8e3e569dc49f2a1018d1dc9186998
#include <stdio.h>
int main() {
int x,y,x1,y1;
scanf("%d %d\n %d %d",&x,&y,&x1,&y1);
if(y1-y==1){
printf("u");
}else if(y1-y==-1){
printf("d");
}else if(x1-x==1){
printf("r");
}else if(x1-x==-1){
printf("l");
}
}
