题解 | #比较版本号#

class Solution:
    def compare(self , version1: str, version2: str) -> int:
        # write code here
        f=lambda a:''.join([i.rjust(30,'0') for i in a.split('.')])+''.join(['0'*30]*(3-len(a.split('.'))))
        version1=f(version1)
        version2=f(version2)
        if version1>version2:
            return 1
        elif version1<version2:
            return -1
        else:
            return 0