题解 | #牛牛的计划#
牛牛的计划
https://www.nowcoder.com/practice/cf956ceef9f84f7393a0b7284fdbf95a
#include <stdio.h>
int main() {
int y, m, d, y1, m1, d1;
scanf("%d %d %d\n%d %d %d", &y, &m, &d, &y1, &m1, &d1);
if (y < y1) {
printf("yes");
}
else if (y == y1) {
if (m<=m1) {
if (d<=d1) {
printf("yes");
}
else {
printf("no");
}
}
}
else {
printf("no");
}
return 0;
}
