题解 | #字符串反转#
字符串反转
https://www.nowcoder.com/practice/e45e078701ab4e4cb49393ae30f1bb04
// 字符串接受数据并判断输入的规范性再用StringBuilder追加写入，处理完反转
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String str = new String(sc.nextLine());
StringBuilder sb = new StringBuilder();
for (int i = 0; i < str.length(); i++) {
if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z') {
sb.append(str.charAt(i));
}else{
System.out.println("输入不规范，请重新输入");
break;
}
}
System.out.println(sb.reverse());
}
}
