题解 | #时间转换#
时间转换
https://ac.nowcoder.com/acm/contest/18839/1031
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a;
cin>>a;
int h=a/3600;
int min=(a-3600*h)/60;
int s=a-3600*h-min*60;
cout<<h<<" "<<min<<" "<<s<<endl;
}
