题解 | #接口#
接口
https://www.nowcoder.com/practice/8f91b606181746558e8a398e513d1078
间接高效
let data = [
{name: 'nowcoder1'},
{name: 'nowcoder2'}
]
const _api = string => {
// 补全代码
let getIndex = string.indexOf('get?');
let updateIndex = string.indexOf('update?');
if (getIndex > -1) return data;
else if (updateIndex > -1) {
let querystr = string.slice(updateIndex).split('&')
let name = querystr[0].split('=')[1];
let to = querystr[1].split('=')[1]
data.filter(v => v.name == name)
.forEach(v => v.name = to);
return data;
}
}
