题解 | #序列重组矩阵#
序列重组矩阵
https://www.nowcoder.com/practice/7548f8f5e44c42fa84fb2323d899a966
n,m=map(int,input().split())
a=input()
for i in range(n):
print(a[2*m*i:2*m*i+2*m])
a=input()
for i in range(n):
print(a[2*m*i:2*m*i+2*m])
序列重组矩阵
https://www.nowcoder.com/practice/7548f8f5e44c42fa84fb2323d899a966
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