题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
let line=readline().split(' ')
let len=line.shift(),
head=line.shift(),
tar=line.pop();
let ans=[head],i=0;
while(i<line.length){
let t =line[i+1],n=line[i];
let index=ans.indexOf(t)
ans.splice(index+1,0,n)
i+=2
}
let tarIndex=ans.indexOf(tar)
ans.splice(tarIndex,1)
console.log(ans.join(' '))
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