题解 | #计算日期到天数转换#

#include<stdio.h>
int main(void)
{
    int year,month,day;
    scanf("%d %d %d",&year,&month,&day);
    int monthday[12]={31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    int daycnt=0;
    if(year%400==0||year%100!=0&&year%4==0)
    {
        monthday[1]++;
    }
    for(int i=0;i<month-1;i++)
    {
        daycnt+=monthday[i];
    }
    daycnt+=day;
    printf("%d",daycnt);
    return 0;
}