题解 | #数组元素反转#
数组元素反转
https://www.nowcoder.com/practice/8c9793ae96974a9ebb153d90ef31d357
折半交换，根据下标之和
为 len-1 进行交换。
#include <iostream>
using namespace std;
int main() {
int arr[6] = { 0 };
int len = sizeof(arr) / sizeof(int);
for (int i = 0; i < len; i++)
{
cin >> arr[i];
}
cout << "[";
for (int i = 0; i < len; i++)
{
if (i == len - 1)
{
cout << arr[i] << "]" << endl;
break;
}
cout << arr[i] << ", ";
}
// write your code here......
for (int i = 0; i < len / 2; ++i)
{
int tmp = arr[i];
arr[i] = arr[len - 1 - i];
arr[len - 1 - i] = tmp;
}
cout << "[";
for (int i = 0; i < len; i++)
{
if (i == len - 1)
{
cout << arr[i] << "]" << endl;
break;
}
cout << arr[i] << ", ";
}
return 0;
}
为 len-1 进行交换。
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